Problem48.py

# Code by @AmirMotefaker

# projecteuler.net
# https://projecteuler.net/problem=48

# Self powers
# Problem 48

# The series, 1**1 + 2**2 + 3**3 + ... + 10**10 = 10405071317.

# Find the last ten digits of the series, 1**1 + 2**2 + 3**3 + ... + 1000**1000.

# Solution 1

import time
start_time = time.time()   #Time at the start of program execution

solution = 0

for i in range(1, 1001):
    solution += i**i

print (str(solution)[-10:])   # printing the last 10 digits

end_time = time.time()   #Time at the end of execution
print ("Time of program execution:", (end_time - start_time))   # Time of program execution



# Solution 2

# import time
# start_time = time.time()   #Time at the start of program execution

# def main():
#     total = 0
#     for i in range(1,1001):
#         total += i**i
#     print(str(total)[-10:])


# main()

# end_time = time.time()   #Time at the end of execution
# print ("Time of program execution:", (end_time - start_time))   # Time of program execution



### Answer:  9110846700