Two articles on C++ added

GFG Articles/Udhay_Brahmi_GFG/Find the Work done by force with displacement..cpp

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+/*Given two strings representing force and displacement.Consider a situation in which Force (F)acts on a particle and the displacement of the point of application is given as (D). The task is to find Work Done (W). 
+
+W=F(ai+bj+ck).D(di+ej+fk) or W= a.d + b.e + c.f 
+
+where a,b,c,d,e,f are variables.
+
+Implementation in C++ */
+#include <bits/stdc++.h>
+#include<sstream>
+using namespace std;
+
+int main() {
+
+    //Force
+    string a="20i+31j-67k";
+
+    //Displacement
+    string b="3i+1j+765k";
+
+    //To store i,j,k values of force.
+    string i1="",j1="",k1="";
+
+    //Used to allow digits to be stored in their respective variables.
+    bool gi1=true,gj1=false,gk1=false;
+
+//FORCE   
+    //Extracting Force values from string a and store them in i1,j1,k1.
+    for(int i=0;i<(a.length()-1);i++){
+        if(a[i]=='i'){gi1=false;gj1=true;continue;}
+        if(a[i]=='j'){gi1=false;gj1=false;gk1=true;continue;}
+        if(gi1){i1+=a[i];}//Storing i value in i1
+        if(gj1){j1+=a[i];}//Storing j value in j1
+        if(gk1){k1+=a[i];}//Storing k value in k1
+    }
+//DISPLACEMENT 
+    //To store i,j,k values of Displacement.
+    string i2="",j2="",k2="";
+
+    //Used to allow digits to be stored in their respective variables.
+    bool gi2=true,gj2=false,gk2=false;
+
+    //Extracting Force values from string a and store them in i1,j1,k1.
+    for(int i=0;i<(b.length()-1);i++){
+        if(b[i]=='i'){gi2=false;gj2=true;continue;}
+        if(b[i]=='j'){gi2=false;gj2=false;gk2=true;continue;}
+        if(gi2){i2+=b[i];}//Storing i value in i2
+        if(gj2){j2+=b[i];}//Storing j value in j2
+        if(gk2){k2+=b[i];}//Storing k value in k2
+    }
+//To convert string i1,j1,k1,i2,j2,k2 -to- integers
+    stringstream geeki1(i1);
+    stringstream geekj1(j1);
+    stringstream geekk1(k1);
+    stringstream geeki2(i2);
+    stringstream geekj2(j2);
+    stringstream geekk2(k2);
+    int f1=0,f2=0,f3=0,d1=0,d2=0,d3=0;
+    geeki1>>f1;
+    geekj1>>f2;
+    geekk1>>f3;
+    geeki2>>d1;
+    geekj2>>d2;
+    geekk2>>d3;
+
+    //To add + and - sign
+    string str,sty,stm;
+
+    // For i
+    if((f2*d2)>0)str="+";
+    else{str="-";}
+
+    //For j
+    if((f1*d1)>0){stm="+";}
+    else{stm="-";}
+
+    //For k
+    if((f3*d3)>0)sty="+";
+    else{sty="-";}
+
+    //Printing result
+    cout<<stm<<abs(f1*d1)<<"i"<<str<<abs(f2*d2)<<"j"<<sty<<abs(f3*d3)<<"k"<<endl;
+	return 0;
+}

GFG Articles/Udhay_Brahmi_GFG/Sum of digits after finding absolute difference between two number one is reverse of other..cpp

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+/*Given a number say(N).The task is to perform the following steps on N:-
+
+1:- First find the new number(say M) after reversing the digits of N.
+
+2:-Find the absolute difference between M and N , say(K).
+
+3:-Sum the digits of K and print it.
+
+INPUT:- 32347654
+
+N=32347654
+
+M=45674323
+
+Difference:- 13333331
+
+OUTPUT = 20
+
+Approach:-
+
+First divide the string of number N into two equal parts(One starts from index 0 and other from last till middle) 
+and then just simply find the absolute difference between the digits of two strings. 
+*/
+#include <iostream>
+#include<cmath>
+using namespace std;
+int main() {
+	string n="24817",numb1="",numb2="";
+	float length_of_number=n.length();
+	for(int i=0;i<ceil(length_of_number/2);i++) numb1+=n[i];
+	//numb1=248
+	for(int i=(n.length()-1);i>=floor(length_of_number/2);i--) numb2+=n[i];
+	//numb2=718
+	int sum=0;
+	for(int i=0;i<numb1.length();i++) sum+=abs(numb1[i]-numb2[i]);
+	cout<< (2*sum) <<endl;
+	return 0;
+}